y=sin^2(2-3x)求导
问题描述:
y=sin^2(2-3x)求导
答
y=sin²(2-3x)
y′=2sin(2-3x)[sin(2-3x)]′
=2sin(2-3x)cos(2-3x)(2-3x)′
=-3sin[2(2-3x)]