f(x)是偶函数,则有序实数对(a,b)可以是
问题描述:
f(x)是偶函数,则有序实数对(a,b)可以是
f(x)=asin(x+π/4)+bsin(x-π/4)(a不等于b)
答
f(x)=f(-x)
f(x)=asin(x+π/4)+bsin(x-π/4)
f(-x)=asin(-x+π/4)+bsin(-x-π/4)
=-bsin(x+π/4)-asin(x-π/4)
即任意a=-b时成立