已知tanx=根号下7,求(1--cos2x+sin2x)/(1+cos2x+sin2x)的值(请写过程)

问题描述:

已知tanx=根号下7,求(1--cos2x+sin2x)/(1+cos2x+sin2x)的值(请写过程)

(1--cos2x+sin2x)/(1+cos2x+sin2x)=(1-(1-2sin^x)+2sinxcosx)/(1+(2cos^x-1)+2sinxcosx)=(2sin^x+2sinxcosx)/(2cos^x+2sinxcosx)=(sinx/cosx)[(sinx+cosx)/(cosx+sinx)]=sinx/cosx=tanx=根号7