数列an满足a1=1,an=an-1+1/n方-n（n大于等于2）,求an通项
问题描述：
数列an满足a1=1,an=an-1+1/n方-n（n大于等于2）,求an通项
答
an=a(n-1)+1/(n²-n)=a(n-1)+1/(n-1)-1/nan+1/n=a(n-1)+1/(n-1)an+1/n=a(n-1)+1/(n-1)=a(n-2)+1/(n-2)=...=a1+1/1=1+1=2an=2-1/n=(2n-1)/nn=1时,a1=(2-1)/1=1,同样满足.数列{an}的通项公式为an=(2n-1)/n...