等边△ABC边长为8,D为AB边上一动点,过点D作DE⊥BC于点E,过点E作EF⊥AC于点F. (1)若AD=2,求AF的长; (2)求当AD取何值时,DE=EF.
问题描述:
等边△ABC边长为8,D为AB边上一动点,过点D作DE⊥BC于点E,过点E作EF⊥AC于点F.
(1)若AD=2,求AF的长;
(2)求当AD取何值时,DE=EF.
答
(1)∵AB=8,AD=2∴BD=AB-AD=6在Rt△BDE中∠BDE=90°-∠B=30°∴BE=12BD=3∴CE=BC-BE=5在Rt△CFE中∠CEF=90°-∠C=30°∴CF=12CE=52∴AF=AC-FC=112;(2)在△BDE和△EFC中∠BED=∠CFE=90°∠B=∠CDE=EF,∴△B...