2sin(x-π/4)sin(x+π/4)=(sinx-cosx)(sinx+cosx)=-cos2a而我做的2sin(x-π/4)sin(x+π/4)=2cos(x+π/4)sin(x+π/4)=sin(2x+π/2)=cos2a差个符号?

问题描述:

2sin(x-π/4)sin(x+π/4)=(sinx-cosx)(sinx+cosx)=-cos2a
而我做的2sin(x-π/4)sin(x+π/4)=2cos(x+π/4)sin(x+π/4)=sin(2x+π/2)=cos2a
差个符号?

要用这个公式,你用错了cos(π/2+a)=-sinasina=-cos(π/2+a)2sin(x-π/4)sin(x+π/4)=-2cos[π/2+(x-π/4)]sin(x+π/4)=-2cos(x+π/4)sin(x+π/4)=-sin(2x+π/2)=...