若a>1,b>1,log2b×log2a=16,则log2(ab)的最小值为____
问题描述:
若a>1,b>1,log2b×log2a=16,则log2(ab)的最小值为____
答
log2(ab)=log2a+log2b
>=2根号(log2a*log2b)
=8