已知实数m、n满足mn=2,m+2n=8,求代数式2m^2n+4mn^2的值

问题描述:

已知实数m、n满足mn=2,m+2n=8,求代数式2m^2n+4mn^2的值

解答如下:
2m²n + 4mn²
=2mn(m + 2n)
= 2 * 2 * 8 = 32

2m^2n+4mn^2
=2mn(m+2n)
=2×2×8
=32