若x,y满足y<x-2+2-x+4,化简|y-4|-y2-10y+25.

问题描述:

若x,y满足y<

x-2
+
2-x
+4,化简|y-4|-
y2-10y+25

由题意可得:x-2≥0,2-x≥0,联立可得x=2,
y<

x-2
+
2-x
+4可变形为y-4<
x-2
+
2-x

所以y-4<0,y<4,则
|y-4|=4-y,
y2-10y+25
=
(y-5)2
=5-y,
则|y-4|-
y2-10y+25
=4-y-5+y=-1
则可得答案为:-1.