如果有理数a为2,b为1求ab分之1+(a+1)(b+1)分之1+.(a+2004)(b+2004)分之1

问题描述:

如果有理数a为2,b为1求ab分之1+(a+1)(b+1)分之1+.(a+2004)(b+2004)分之1

ab分之1+(a+1)(b+1)分之1+.(a+2004)(b+2004)分之1
=1/1×2+1/2×3+1/3×4+……+1/2005×2006
=1-1/2+1/2-1/3+1/3-1/4+……+1/2005-1/2006
=1-1/2006
=2005/2006