求经过直线L1:3x+y-6=0与L2:2x+3y+3=0的交点,且平行于直线L3:x+2y-8=0的直线方程.
问题描述:
求经过直线L1:3x+y-6=0与L2:2x+3y+3=0的交点,且平行于直线L3:x+2y-8=0的直线方程.
答
3x+y-6=0.(1)
2x+3y+3=0.(2)
(1),(2):
交点(3,-3)
L3:y+3=(-1/2)*(x-3)
x+2y+3=0