4xy-[(x²+5xy-y²)-(x²+3xy-2y²)],其中x=2,y=-1求值,化简
问题描述:
4xy-[(x²+5xy-y²)-(x²+3xy-2y²)],其中x=2,y=-1
求值,化简
答
4xy-[(x²+5xy-y²)-(x²+3xy-2y²)]
=4xy-(x²+5xy-y²-x²-3xy+2y²)
=4xy-(2xy+y²)
=4xy-2xy-y²
=2xy-y²
=y(2x-y)
=(-1)x(2x2+1)
=-5
答
4xy-[(x²+5xy-y²)-(x²+3xy-2y²)]=4xy-(x²+5xy-y²-x²-3xy+2y²)=4xy-(2xy+y²)=2xy-y²=(2x-y)y=(2x2+1)x(-1)=-5