求y=cos(x-2)的导数要有详细过程哦.谢谢

问题描述:

求y=cos(x-2)的导数
要有详细过程哦.谢谢

y'=-sin(x-2)

详细的话:
Let u = x-2, y=cos (u)
du/dx = 1
dy/du = -sin (u)
since, dy/dx = dy/du * du/dx
dy/dx = -sin (x-2)

公式:(cosx)'=-sinx
y'=-sin(x-2)*(x-2)'(复合函数求导)
=-sin(x-2)*1
=-sin(x-2)