已知f{x}=2sin x + x³ +1 ,若f{a}=3,则f{-a}=?
问题描述:
已知f{x}=2sin x + x³ +1 ,若f{a}=3,则f{-a}=?
答
f{-x}=2sin(- x )+ (-x)³ +1
=-2sinx-x³ +1
=-(2sin x + x³ +1 )+2
=-f{x}+2
f{a}=3,则
f{-a}=-f{a}+2=-3+2=-1
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