用换元法解方程[6(x+1)/(x^2)+x^2/(x+1)]=7,若设x^2/x+1=y,则原方程可化为
问题描述:
用换元法解方程[6(x+1)/(x^2)+x^2/(x+1)]=7,若设x^2/x+1=y,则原方程可化为
答
32-1*8huhi
答
设x^2/x+1=y,则原方程可化为
6/y+y=7