换元法解方程x/(x-1)+[3(x-1)/x]-2=0时,设x/(x-1)=y,方程可化为整式方程为?
问题描述:
换元法解方程x/(x-1)+[3(x-1)/x]-2=0时,设x/(x-1)=y,方程可化为整式方程为?
A.y²-2y+3=0 B.y²+2y+3=0
C.y²+3y-2=0 D.y+3/y-2=0
答
选Dy+3/y-2=0