已知cosa=-3/5,求cos(a-π/2)+2sin(3π-a)/2tan(3π+a)+cot(π/2+a)
问题描述:
已知cosa=-3/5,求cos(a-π/2)+2sin(3π-a)/2tan(3π+a)+cot(π/2+a)
答
[cos(a-π/2)+2sin(3π-a)]/[2tan(3π+a)+cot(π/2+a)]
=[sina+2sina]/[2tana-tana]
=3sina/tana
=3cosa
=3*(-3/5)
=-9/5