计算:[x(x2y2-xy)-y(x2-x3y)]÷3x2y.
问题描述:
计算:[x(x2y2-xy)-y(x2-x3y)]÷3x2y.
答
原式=(x3y2-x2y-x2y+x3y2)÷3x2y
=(2x3y2-2x2y)÷3x2y
=
xy-2 3
.2 3