化简1+sin40°-cos40°/1+sin40°+cos40°

问题描述:

化简1+sin40°-cos40°/1+sin40°+cos40°

=1+2sin20°cos20°-(1-2sin²20°)/1+2sin20°cos20°+(2cos²20°-1)
=2sin20°cos20°+2sin²20°/2sin20°cos20°+2cos²20°
=2sin20°(cos20°+sin20°)/2cos20°(sin20°+cos20°)
=2sin20°/2cos20°
=tan20°
自己蒙的,不知对不对

1+sin40°-cos40°/1+sin40°+cos40°
=(2sin^220°+2sin20°cos20°)/(2sin20°cos20°+2cos^2 20°)
=2sin20°(sin20°+cos20°)/2cos20°(sin20°+cos20°)
=tan20°

1+sin40-cos40=1+2sin20cos20-(1-2sin²20)=2sin20cos20+2sin²20=2sin20(sin20+cos20)1+sin40+cos40=1+2sin20cos20+2cos²20-1=2cos20(sin20+cos20)(1+sin40-cos40)/(1+sin40+cos40)=2sin20(sin20+cos2...

( 1 + cos40 )/ sin40 = sin40 /( 1 - cos40 ) = (1 + sin40?+ cos40 )/( 1 + sin40 -cos40 )
( 1 + cos40 )/ sin40 = 2(cos20)^2 / (2sin20cos20) = cot20
所以原式=cot20