1/2+1/6+1/12+`````+1/n(n+1)=2003/2004,n为多少?
问题描述：
1/2+1/6+1/12+`````+1/n(n+1)=2003/2004,n为多少?
答
方程可化为
1-1/2+1/2-1/3+1/3-...+1/(n+1)-1/(n-1)=2003/2004
1-1/(n+1)=2003/2004
n/(n+1)=2003/2004
2004n=2003n+2003
n=2003