(x^2-ax+2)/(x^2-x-1)
问题描述:
(x^2-ax+2)/(x^2-x-1)
答
y=(x^2-ax+2)/(x^2-x-1)==0
yy-2ay+aa+4yy+4y-8>=0
5yy+(4-2a)y+(aa-8)>=0
(y-?)(y-3)