已知等比数列{an}中,a1+a2=9,a1a2a3=27,则{an}的前n项和Sn=_.

问题描述:

已知等比数列{an}中,a1+a2=9,a1a2a3=27,则{an}的前n项和Sn=______.

解∵a1a2a3=27,
∴a2=3,
又∵a1+a2=9
∴a1=6,公比q=

1
2

∴Sn=
6[1−(
1
2
)
n
]
1−
1
2
=12[1-(
1
2
n]
故答案为12[1-(
1
2
n].