积分（x^2+4x+4)/(x(x-1)^2)
问题描述：
积分（x^2+4x+4)/(x(x-1)^2)
答
（x^2+4x+4)/(x(x-1)^2)=4/x-3/(x-1)+9/(x-1)^2
∫（x^2+4x+4)/(x(x-1)^2)dx=∫[4/x-3/(x-1)+9/(x-1)^2]dx
=4*ln|x|-3ln|x-1|-9/(x-1)+c