A^logcB=B^logcA怎么证明?

问题描述:

A^logcB=B^logcA怎么证明?

很简单的,两边同取以c为底的对数
logcA^logcB=logcB*logcA
logcB^logcA=logcA*logcB
所以logcA^logcB=logcB^logcA
得A^logcB=B^logcA