A^logcB=B^logcA怎么证明?
问题描述:
A^logcB=B^logcA怎么证明?
答
很简单的,两边同取以c为底的对数
logcA^logcB=logcB*logcA
logcB^logcA=logcA*logcB
所以logcA^logcB=logcB^logcA
得A^logcB=B^logcA