a(a+b)(a-b)-a(a-b)^2,提公因式
问题描述：
a(a+b)(a-b)-a(a-b)^2,提公因式
答
2ab(a-b)
答
提a(a-b)
a(a+b)(a-b)-a(a-b)^2
=a(a-b)[(a+b)-(a-b)]
=2ab(a-b)
答
a(a+b)(a-b)-a(a-b)^2
=a(a+b)(a-b)-a(a-b)(a-b)
=a(a-b)[(a+b)-(a-b)]
=a(a-b)(a+b-a+b)
=ab^2(a-b)
答
a(a-b){(a+b)-2}