∠ABC=31º,由AC的延长线引出E,∠BAC的平分线AE与∠FCB的平分线CE相交于点E,则∠AEC为()
问题描述:
∠ABC=31º,由AC的延长线引出E,∠BAC的平分线AE与∠FCB的平分线CE相交于点E,则∠AEC为()
答
∠ABC=31º,由AC的延长线引出E,∠BAC的平分线AE与∠FCB的平分线CE相交于点E,则∠AEC为()