若函数y=sin wx * cos wx (w>0)的最小正周期为4π,则常数w=A 1/4B 1/2C 2D 4
问题描述：
若函数y=sin wx * cos wx (w>0)的最小正周期为4π,则常数w=
A 1/4
B 1/2
C 2
D 4
答
原式=sin(2wx)/2
最小正周期为4π
2π/2w=4π
2w=1/2
w=1/4
答
because :2sinx*cosx=sin2xso,y=1/2sin2wxT= 4π,so,2w = 2π/4 π,so,w=1/4so,the answer is Ai dont know why i cant tape the chinese in the end .but i also want you can use my answer thank you.im also a h...