设x=(log1/2底1/3)^-1+(log1/5底1/3)^-1,若x属于(k,k+1),则k
问题描述：
设x=(log1/2底1/3)^-1+(log1/5底1/3)^-1,若x属于(k,k+1),则k
答
x=1/log(1/2)(1/3)+1/log(1/5)(1/3)
=log3(2)+log3(5)
=log3(10)
log3(9)