已知等式(x-1 )5=ax5+bx4+cx3+dx2+ex+f,则求a+b+c+d+e+f=,-a+b-c+d-e=
问题描述:
已知等式(x-1 )5=ax5+bx4+cx3+dx2+ex+f,则求a+b+c+d+e+f=,-a+b-c+d-e=
答
令x=1,则(1-1 )5=a+b+c+d+e+f,所以a+b+c+d+e+f=0令x=-1,则(-1-1 )5=-a+b-c+d-e+f,所以-a+b-c+d-e=-32
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