已知2n-m-5=0,求5(m-2n)²-3(m-2n)-60的值写出具体过程
问题描述：
已知2n-m-5=0,求5(m-2n)²-3(m-2n)-60的值
写出具体过程
答
由2n-m-5=0知 m-2n=-5;
5(m-2n)²-3(m-2n)-60
=5×25+3×5-60
=80
答
解2n-m-5=0
即2n-m=5
即m-2n=-5
即5(m-2n)²-3(m-2n)-60
=5(-5)²-3(-5)-60
=5*5²+15-60
=125+15-60
=80
答
2n-m-5=0
m-2n=-5
5(m-2n)²-3(m-2n)-60
=5x(-5)²-3x(-5)-60
=125+15-60
=140-60
=80
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答
2n-m-5=0
m-2n=-5
5(m-2n)²-3(m-2n)-60
=5*(-5)²-3*(-5)-60
=125+15-60
=80