2cos9π/13*cosπ/13=[cos(9π/13+π/13)+cos(9π/13-π/13)]怎么化?

问题描述:

2cos9π/13*cosπ/13=[cos(9π/13+π/13)+cos(9π/13-π/13)]怎么化?

公式cos(α+β) =cosαcosβ-sinαsinβ,cos(α-β)= cosαcosβ+sinαsinβ
cos(α+β)+cos(α-β)
=(cosαcosβ-sinαsinβ)+(cosαcosβ+sinαsinβ)
=2cosαcosβ
反套就可以了.