32/8^n-1=2^n,则n=____
问题描述：
32/8^n-1=2^n,则n=____
答
32/8^(n-1)=2^n
2^5/[(2^3)^(n-1)]=2^n
2^5/[2^(3n-3)]=2^n
2^[5-(3n-3)]=2^n
2^[5-3n+3]=2^n
2^[8-3n]=2^n
8-3n=n
4n=8
n=2