(tanx)dy/dx=1+y求通解
问题描述：
(tanx)dy/dx=1+y求通解
答
tanx•dy/dx = 1 + y
dy/dx•1/(1 + y) = cotx
dy/(1 + y) = cotxdx
ln|1 + y| = ln|sinx| + lnC = ln|C•sinx|
1 + y = C•sinx
y = C•sinx - 1