求x^2-4xy-1+4y^2的解
问题描述:
求x^2-4xy-1+4y^2的解
x^2-4xy-1+4y^2
答
(x-2y+1)(x-2y-1)过程呢?(x-2y)^2-1 = (x-2y)^2-1^2 = (x-2y+1)(x-2y-1)
求x^2-4xy-1+4y^2的解
x^2-4xy-1+4y^2
(x-2y+1)(x-2y-1)过程呢?(x-2y)^2-1 = (x-2y)^2-1^2 = (x-2y+1)(x-2y-1)