化简y=sin(2x-π/3)+√3cos2x,急救!
问题描述:
化简y=sin(2x-π/3)+√3cos2x,急救!
将y=sin(2x-π/3)+√3cos2x(“√”是根号)
化简为y=Asin(ωx+φ)的形式
jiayu20442 :那“+√3cos2x”怎么突然没了?
答
y=sin2xcosπ/3-sinπ/3cos2x+√3cos2x
=sin2xcosπ/3-(√3cos2x)/2+√3cos2x
=sin2xcosπ/3+(√3cos2x)/2
=sin2xcosπ/3+sinπ/3cos2x
=sin(2x+π/3)