配方x^2+y^2+4z^2+4x+6y+12z+22
问题描述:
配方x^2+y^2+4z^2+4x+6y+12z+22
答
x²+y²+4z²+4x+6y+12z+22=x²+y²+4z²+4x+6y+12z+4+9+9=x²+4x+4+y²+6y+9+4z²+12z+9=(x+2)²+(y+3)²+(2z+3)²
配方x^2+y^2+4z^2+4x+6y+12z+22
x²+y²+4z²+4x+6y+12z+22=x²+y²+4z²+4x+6y+12z+4+9+9=x²+4x+4+y²+6y+9+4z²+12z+9=(x+2)²+(y+3)²+(2z+3)²