x^2y^2-3xy-4和3m^2+6m-2

问题描述:

x^2y^2-3xy-4和3m^2+6m-2

答:
x^2*y^2-3xy-4
=(xy)^2-3xy-4
=(xy-4)(xy+1)
3m^2+6m-2
=3(m^2+2m+1)-5
=3(m+1)^2-5
=[√3(m+1)-√5]*[√3(m+1)+√5]