设实数ab满足log2(a-1)+log2(b-2)=2则a+b的最小值为
问题描述:
设实数ab满足log2(a-1)+log2(b-2)=2则a+b的最小值为
答
(a-1)(b-2)=4
a+b=(a-1)+(b-2)+3大于等于2根号(a-1)+(b-2) +3
故a+b的最小值为5