急求∫(上限π/2,下限-π/2)(x^3+sin^2x)cos^2xdx=
问题描述：
急求∫(上限π/2,下限-π/2)(x^3+sin^2x)cos^2xdx=
答
x^3cos^2xdx+sin^2xcos^2xdx
x^3cos^2x是奇函数所以它的定积分为0
算出得0