已知sin(x-60°)=2/3,求sin(x+60°)-根号3cos(120°-x)的值

问题描述:

已知sin(x-60°)=2/3,求sin(x+60°)-根号3cos(120°-x)的值

sin(x+60°)-根号3cos(120°-x)=sinxcos60°+cosxsin60°-根号3(cos120°cosx+sin120°sinx)=sinx/2+根号3cosx/2-根号3(-cosx/2+根号3sinx/2)=-sinx+根号3cosx=-2(sinx/2-根号3cosx/2)=-2sin(x-60°)=-4/3...