等差数列中,a1=-3,11a5=5a8,则sn
问题描述：
等差数列中,a1=-3,11a5=5a8,则sn
答
11(a1+4d)=5(a1+7d)
: a1=-3
d=2
Sn=-3n+{n(n-1)2}/2=n^2-4n
答
11a5=5a8
11*(a1+4d)=5*(a1+7d)
11a1+44d=5a1+35d
6a1=-9d
2a1=-3d
2*(-3)=-3d
d=2
an=a1+(n-1)d
=-3+2(n-1)
=2n-5
sn=(a1+an)*n/2
=(-3+2n-5)*n/2
=n(n-4)