解方程:(1)2(x+3)-5(1-x)=3(x-1);(2)2y-3[y-4(1-2y)-5]=0.

问题描述:

解方程:(1)2(x+3)-5(1-x)=3(x-1);(2)2y-3[y-4(1-2y)-5]=0.

2(x+3)-5(1-x)=3(x-1)
x=7/6
2y-3[y-4(1-2y)-5]=0
y=27/25第一题能说下详细过程么2(x+3)-5(1-x)=3(x-1)2x+6-5+5x=3x-34x=-1x=-1/4额,到底是多少?2(x+3)-5(1-x)=3(x-1)2x+6-5+5x=3x-34x=-1x=-1/4