1/[n(n+1)]+1/[(n+1)(n+2)]+1/[(n+2)(n+3)]+1/[(n+3)(n+4)]+[(n+4)(n+5)}怎么算谢谢了,
问题描述:
1/[n(n+1)]+1/[(n+1)(n+2)]+1/[(n+2)(n+3)]+1/[(n+3)(n+4)]+[(n+4)(n+5)}怎么算谢谢了,
答
1/[n(n+1)]=1/n-1/(n+1) 因此,上式=(1/n-1/(n+1))+(1/(n+1)-1/(n+2))+...+(1/(n+4)-1/(n+5)) =1/n-1/(n+5) =5/[n(n+5)]