y=cos^2x+根号3sinxcosx+1化成y=Asin(ωx+ψ)+b
问题描述:
y=cos^2x+根号3sinxcosx+1化成y=Asin(ωx+ψ)+b
答
y=cos²x+√3sinxcosx+1
=(1+cos2x)/2+√3sinxcosx+1
=(1/2)cos2x+(√3/2)sin2x+3/2
=sin(2x+π/6)+3/2.