5x^2-4xy+y^2-2x+1=0
问题描述:
5x^2-4xy+y^2-2x+1=0
求(x-y)^2002的值
在线~急~~
答
5x^2-4xy+y^2-2x+1=0
4x^2-4xy+y^2+x^2-2x+1=0
(2x-y)^2+(x-1)^2=0
2x=y
x=1
y=2
(x-y)^2002的值=1