(3x+1)²-4=0 5x²-7x-6=0 25x²-10-1=0 用分解因式发做,
问题描述:
(3x+1)²-4=0 5x²-7x-6=0 25x²-10-1=0 用分解因式发做,
答
用平方法差公式或者十字相乘法因式分解
答
(3x+1)²-4=0
(3x+1+2)(3x+1-2)=0
3x+3=0 3x-1=0
x1=-1 x2=1/3
5x²-7x-6=0
(5x+3)(x-2)=0
5x+3=0 x-2=0
x1=-3/ x2=2
25x²-10-1=0
(5x+3)(5x-3)=0
5x+3=0 5x-3=0
x1=-3/5 x2=3/5