若函数f(x)是以π/2为最小正周期的函数,且f(π/3)=1,求f(17π/6)谢谢了,
问题描述:
若函数f(x)是以π/2为最小正周期的函数,且f(π/3)=1,求f(17π/6)谢谢了,
答
因为f(x)是以π/2为最小正周期的函数,所以有f(x)=f(x+π/2) 经过变换后f(17π/6)=f(π/3)=1
若函数f(x)是以π/2为最小正周期的函数,且f(π/3)=1,求f(17π/6)谢谢了,
因为f(x)是以π/2为最小正周期的函数,所以有f(x)=f(x+π/2) 经过变换后f(17π/6)=f(π/3)=1