若函数f(x)是以π/2为最小正周期的函数,且f(π/3)=1,求f(17π/6)谢谢了,

问题描述:

若函数f(x)是以π/2为最小正周期的函数,且f(π/3)=1,求f(17π/6)谢谢了,

因为f(x)是以π/2为最小正周期的函数,所以有f(x)=f(x+π/2) 经过变换后f(17π/6)=f(π/3)=1