设方程2x^2+3x+1=0的根为x1,x2 求1/x1+1/x2的值.

问题描述:

设方程2x^2+3x+1=0的根为x1,x2 求1/x1+1/x2的值.

x1*x2=c/a=1/2
X1+X2= -b/a =-3/2
1/x1+1/x2
=(x1+x2)/x1x2
=(-3/2)/(1/2)
=-3
1/x1+1/x2的值是-3