求y=arctan[2x/(1-x^2）]的导数,
问题描述：
求y=arctan[2x/(1-x^2）]的导数,
我
时间紧迫啊……
答
y=arctan[2x/(1-x^2）] y=arctanu u=2x/(1-x^2) u'=(2(1-x^2)-2x(-2x))/(1-x^2)^2=(2x^2+2)/(1-x^2)^2那么导数 y'=1/(1+u^2)*u'=1/(1+4x^2/(1-x^2)^2) * ( 2x^2+2)/(1-x^2)^2=( 2x^2+2)/((1-x^2)^2+4x^2) 底下是个完...