已知函数F(x)=X/(x+1),则f(1/2004)+f(1/2003)+……+ f(0)+f(1)+f(2)……+f(2004)=

问题描述:

已知函数F(x)=X/(x+1),则f(1/2004)+f(1/2003)+……+ f(0)+f(1)+f(2)……+f(2004)=

f(x)+f(1/x)=1
f(1/2004)+f(1/2003)+…+ f(0)+f(1)+f(2)…+f(2004)
=f(1/2004)+f(1/2003)+…+f(1/2)+f(1/1)+ f(0)+f(1)+f(2)…+f(2004)
=2004+f(0)
=2004